a 1 RF RF2 Wte Wto d ET, = 0 = (RF20) – (Wtp)(d) - (Wt.)('/21) A 75 kg, 1.75 m tall person lays on a 3 kg, 2 m long boar
Posted: Tue May 17, 2022 9:36 pm
- A 1 Rf Rf2 Wte Wto D Et 0 Rf20 Wtp D Wt 21 A 75 Kg 1 75 M Tall Person Lays On A 3 Kg 2 M Long Boar 1 (36.47 KiB) Viewed 73 times