a 1 RF Wte RF₂ Wto d ET, = 0) = (RF2)O) - (Wtp)(d) - (Wty)('/21) A 75 kg 1.75 m tall person lays on a 3 kg, 2 m long boa
Posted: Tue May 17, 2022 9:36 pm
- A 1 Rf Wte Rf Wto D Et 0 Rf2 O Wtp D Wty 21 A 75 Kg 1 75 M Tall Person Lays On A 3 Kg 2 M Long Boa 1 (31.37 KiB) Viewed 67 times