Answer Happy

Question 4. You genotype a population of 100 individuals and identify 50AA, 40 Aa and 10 aa individuals. You determine the expected number of individuals in the population if the population was in Hardy Weinberg Equilibrum (part c) and perform a chi square test. Table 11.5 Chi-Square Probabilities dr 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 0.95 0.004 0.10 0.35 0.71 1.15 1.64 2.17 2.73 0.90 0.016 0.21 0.58 1.06 1.61 2.20 2.83 3.49 4.17 4.87 5.58 6.30 7.04 7.79 8.55 0.70 0.15 0.71 1.42 2.20 3.00 383 4.67 5.53 6.39 7.27 8.15 9.03 9.93 10.82 11.72 0.50 0.46 1.39 2.37 3.36 4.35 5.35 6.35 7.34 8.34 9.34 10.34 11.34 12.34 13.34 14.34 Probabilities 0.30 0.20 1.07 1.64 2.41 3.22 3.67 4.64 4.88 5.99 6.06 7.29 7.23 8.56 8.38 9.80 9.52 11.03 10.66 12 24 11.78 13.44 12.90 14.63 14.01 15.81 15.12 16.99 16.22 18.15 17.32 19.31 0.10 2.71 4.61 6.25 7.78 9.24 10.65 12.02 13.36 14.68 15.99 17:28 18.55 19.81 21.06 2231 0.05 3.84 5.99 7.82 9.49 11.07 12.59 14.07 1551 16.92 18.31 19.68 21.03 22.36 23.69 25.00 0.01 6.64 9.21 11.35 13.28 15.09 16.81 18.48 20.09 21.67 23.21 24.73 26.22 27.69 29.14 30.58 0.001 10.83 13.82 16.27 18.47 20.52 22.46 24.32 26.13 27.88 29.59 31.26 32.91 34.53 36.12 37.70 3.94 4.58 5.23 5.89 6.57 7.26 d) You obtain a chi-square value of 0.22. Consult the chi-square table above and determine - is the population in HWE? Use the drop down menus to choose the most accurate answer. The population (Select] in Hardy Weinberg Equilibrium; the probability is [Select] than [ Select) that the difference between the observed and expected is due to chance.