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From the balanced equation of an acid-base reaction and using your experimental data you will do stoichiometric calculat

Posted: Tue May 17, 2022 12:20 pm
by answerhappygod
From The Balanced Equation Of An Acid Base Reaction And Using Your Experimental Data You Will Do Stoichiometric Calculat 1
From The Balanced Equation Of An Acid Base Reaction And Using Your Experimental Data You Will Do Stoichiometric Calculat 1 (28.93 KiB) Viewed 80 times
From the balanced equation of an acid-base reaction and using your experimental data you will do stoichiometric calculation to determine the concentration of acid. Balanced equations: HCl (aq) + NaOH(aq) + NaCl (aq) + H2O(1) H2SO4 (aq) + 2 NaOH (aq) → Na2SO4(aq 1) + H2O(1) Steps for calculation:

LAB REPORT Experiment-11: Acid-Base Titration Name: Date: Data Table-1 Titration of HCl with NaOH Circle the Label on Acid Trial-1 Trial-2 bottle: ABCD Given Molarity of Base 0.3065 0.3065 Trial-3 0.3065 0.15 10.15 20.30 Initial Reading of Acid Burette in mL 10.15 20.25 30.35 Final Reading of Acid Burette in mL Volume of Acid in mL 0.20 19.85 0.60 Initial Reading of Base Burette in mL 19.85 39.70 20.35 Final Reading of Base Burette in mL Volume of Base in mL Volume of Acid in L Volume of Base in L Moles of Base (Max Lhase) Moles of Acid (molto x Molecid/Molehuse) Molarity of Acid (M=molacid Lecid) Average Molarity of HCI Acid = Sum of molarities of all trials / number of Trials = Data Table-2 Titration of H2SO4 with NaOH Trial-1 - Trial-2 Trial-3 Circle the Label on Acid bottle: E F G H : Given Molarity of Base 0.1115 0.1115 0.1115 0.15 10.15 Initial Reading of Acid Burette in mL 20.30 10.15 Final Reading of Acid Burette in ml 20.25 30.35 Volume of Acid in mL 0.20 19.85 0.60 Initial Reading of Base Burette in ml 19.85 39.70 20.35 Final Reading of Base Burette in mL Volume of Base in mL Volume of Acid in L Volume of Base in L Moles of Base (Mbese x Lase) Moles of Acid (molbase x Molecid/Molebase) Molarity of Acid (M=molacid Lacid) Average Molarity of H2SO, Acid=Sum of Molarities of all trials / Number of Trials =