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pH = 12.03 pОН [ОН-] = [H3O+] = (Н3О+] = 4.36 x 10:11 pH pОН [OH-)

Posted: Tue May 17, 2022 12:14 pm
by answerhappygod
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pH = 12.03 pОН [ОН-] = [H3O+] = (Н3О+] = 4.36 x 10:11 pH pОН [OH-)