Answer Happy • AU = NMZZ -(1 - r 4πε, 0 м. (e2 )/4TTE. = 2.307 x 10-28 Jm = 1.747565 (estructura de NaCl) p = 30 pm radios iónicos Mg =

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AU = NMZZ -(1 - r 4πε, 0 м. (e2 )/4TTE. = 2.307 x 10-28 Jm = 1.747565 (estructura de NaCl) p = 30 pm radios iónicos Mg =

Posted: Tue May 17, 2022 11:18 am

by answerhappygod

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AU = NMZZ -(1 - r 4πε, 0 м. (e2 )/4TTE. = 2.307 x 10-28 Jm = 1.747565 (estructura de NaCl) p = 30 pm radios iónicos Mg = 86 pm y 0 = 126 pm Mgo