Answer Happy

thats what i put for #1 is that not the data
5. Based on the data in question 1, calculate the boiling point freezing point, vapor pressure, and osmotic pressure of the solution 6. List the following aqueous solutions in decreasing order of their expected osmotie pressure: 0.08 M NaBr, 0.06 M Cabra minted Drouide briefenlanation for your orderine based on

1 Solution Ch.13. Sec. only 200.9 g of potassium oxalate is dissolved in 2006.6 g of H2O at 20.0°C. The density of the resulting solution is 1.0891 wmi.. In order, determine the weight %, mole fraction, molality, and molarity of the potassium oxalate.

5 Based on the data in question 1, calculate the boiling point, freezing point, vapor pressure, and osmotic pressure of the solution in the following icons solutions in decreasing order of their expected osmotic pressure: 0.08 M NaBr 0.06 M CaBr

Griven Wt. 100 W. Petassium oxalate (takut) = 300-99 wt & Water (solvert) = 2206.68 Density of solution (6) = 1.089mL (1) Weight? = Maus & sonte x100 300-3 (300 9+22060 ( = 12% (2) Male fraction () = Makes of eclutz Males of scution Se pret w how to calculate malu od salute Males of soluts - wer of sluts Polecular wt. of scute And as we know m. = 166.22 = 300.9 = 1.8 56:22 B 18 124.4 PIO *10 Meles of solvent = 2206-6 = 122.59 Male fraction = 1.81 19 (181+122:59) 0.01 (3) Malality - males of salute wt of scurtig 1.8 2206-6 =0.82 (4) Malarity = males of solute x 10' Volume of dation () Dentily = 300-9-2 202.6 Malarity = 1.8180 1-0891 = 2302.4 = 23024 Volume of solution - mass of solution = 0.786

Strong Electrolyte Weak electrolyte Non-electrolytes NH4H2PO4 Na20 CH4 HC104 H2SO3 CH3OH Mg(OH)2 (CH3CH2)3N H2O1 Ba(OH)2 Strong Acid, Salts or Strong Bases are Strong electrolytes, Weak base or weak acids are weak electrolytes. Whereas neutral compounds are non electrolytes.