Solve the following homogeneous differential equation.
Posted: Tue Nov 16, 2021 7:04 am
Solve the following homogeneous differential equation.
у? - x2 (1) y' = ( ху
(2) y' 2xy 2x2 + y2
(3) (3.1 - y) + (x + 3y)' = 0 х
у? - x2 (1) y' = ( ху
(2) y' 2xy 2x2 + y2
(3) (3.1 - y) + (x + 3y)' = 0 х