2K2SO4 (aq) + 2Ba(OH)2 (aq) --> 4KOH (aq) + 2BaSO4 (s) DeltaHrxn= -275 kj/mol
Posted: Tue May 17, 2022 6:59 am
2K2SO4 (aq) + 2Ba(OH)2 (aq) --> 4KOH (aq) + 2BaSO4 (s)
DeltaHrxn= -275 kj/mol
Using the balanced equation and enthalpy of reaction given below, how much energy is released when 43.6 g of Baso, is formed? 2K2SO4 (aq) + 2Ba(OH)2 (aq) 4KOH (aq) + 2BaSO4 (8) AH = -275 ) ma 51.4 kJ 12.8 kJ OOOOO 103 kJ None of these answers 25.7 kJ
DeltaHrxn= -275 kj/mol
- 2k2so4 Aq 2ba Oh 2 Aq 4koh Aq 2baso4 S Deltahrxn 275 Kj Mol 1 (11.58 KiB) Viewed 63 times