K2CO3 (aq)--> SrCO3 (s) + 2KOH (aq)
Posted: Tue May 17, 2022 6:52 am
K2CO3 (aq)--> SrCO3 (s) + 2KOH (aq)
Using the balanced chemical equation below and given that the actual/experimental yield of strontium carbonate is 2.45, what is the percent yield it 2.5 g of potassium carbonate is reacted with excess strontium hydroxide? Kąco, (aq) + Sr(OH)2 (aq) + SCO3(s) + 2KOH (aq) 98% yield 92% yield None of these answers ОООО 49% yield 46% yield
- K2co3 Aq Srco3 S 2koh Aq 1 (11.34 KiB) Viewed 37 times