2P(g) + 10HF(g) --> 2PF5(g) + 5H2(g) Appendix C: P(g): H* = 316.4 kJ/mol, G* = 280.0 kJ/mol, S* = 163.2 J/mol-K HF(g):
Posted: Mon May 16, 2022 11:01 pm
2P(g) + 10HF(g) --> 2PF5(g) + 5H2(g)
Appendix C:
P(g): H* = 316.4 kJ/mol, G* = 280.0 kJ/mol, S* = 163.2 J/mol-K
HF(g): H*= -268.61 kJ/mol, G* = -270.70 kJ/mol, S* = 173.51 J/mol-K
PF5(g): H* = -1594.4 kJ/mol, G* = -1520.7 kJ/mol, S* = 300.8 J/mol-K
H2(g): H* = 0 kJ/mol, G* = 0 kJ/mol, S* = 130.58 J/mol-K
1.) DeltaH =
Express your answer using 5 sig figs.
2.) DeltaG =
Express your answer using 4 sig figs.
Appendix C:
P(g): H* = 316.4 kJ/mol, G* = 280.0 kJ/mol, S* = 163.2 J/mol-K
HF(g): H*= -268.61 kJ/mol, G* = -270.70 kJ/mol, S* = 173.51 J/mol-K
PF5(g): H* = -1594.4 kJ/mol, G* = -1520.7 kJ/mol, S* = 300.8 J/mol-K
H2(g): H* = 0 kJ/mol, G* = 0 kJ/mol, S* = 130.58 J/mol-K
1.) DeltaH =
Express your answer using 5 sig figs.
2.) DeltaG =
Express your answer using 4 sig figs.