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1 a Use the data below to calculate the enthalpy change for the process: C2H5OH) → C2H5OH(9) C2H5OH(1) + 302(g) → 2CO2(g
Posted: Mon May 16, 2022 11:00 pm
by answerhappygod
- 1 A Use The Data Below To Calculate The Enthalpy Change For The Process C2h5oh C2h5oh 9 C2h5oh 1 302 G 2co2 G 1 (48.13 KiB) Viewed 46 times
1 a Use the data below to calculate the enthalpy change for the process: C2H5OH) → C2H5OH(9) C2H5OH(1) + 302(g) → 2CO2(g) + 3H2O(1) AH = -1371 kJ mol-1 C2H5OH(9) + 302(g) 2C02(g) + 3H2O(1) AH = -1415 kJ mol-1 b Use the data below to calculate the enthalpy change for the process: C6H6(1)→ CoH6(9) 2C6H6(0) + 1502(g) → 12CO2(g) + 6H2O(1) AH = -6544 kJ mol-1 2C6H6(g) + 1502(9) 12CO2(g) + 6H2O(1) AH = -6606 kJ mol-1 2 a Use the data below to calculate the enthalpy change for the reaction: BrF(g) + 2F2(g) → BrF5(1) BrF(g) + F2(g) → BrF3(1) AH = -242 kJ mol-1 BrF3(1) + F2(g) → BrF51) AH = -158 kJ mol-1 b Use the data below to calculate the enthalpy change for the reaction: CIF3(9) + F2(g) → C1F5(9) Cl2(g) + 3F2(g) → 2C1F3(9) AH = -328 kJ mol-1 Cl2(g) + 5F2(g) → 2C1F5(9) AH = -510 kJ mol-1 +