Complete all steps.
Posted: Mon May 16, 2022 10:41 pm
Complete all steps.
B с III. (30 Points) Compound A equilibrates with B following a first order rate law, in turn equilibrating with C, also with first order kinetics. The associated thermodynamic and kinetic data are given in the equation shown: E. - 40 kcal mort E = 20 kcal mort А AG* = 0 kcal molt AG* +0 kcal mor! a. Complete the energy diagram below as follows: 1. Starting with A positioned at level "O" (black bar), indicate the respective positions of B and C along the reaction coordinate (use bars and label them with the respective letters), 2. Show the positions of the two respective transition states (bars) that reflect the activation energies of the two steps. Label them TSAB and TSBC", respectively, Potential-Energy Diagram A B с 40 20 А. O -20 40 E (kcal mol-1) Reaction coordinate
9 b. You can monitor the progress of the equilibrations. Place an "X" mark in the box next to the correct statements below (there may be several). A disappears at the same rate at which B+C appears. B converts to C faster than back to A. At full equilibration, the ratio of A:B:C is 1:1:1. In the initial stages of the transformation of A, one can observe a build-up of TSAB The conversion of A follows the rate law: Rate = K[A].
B с III. (30 Points) Compound A equilibrates with B following a first order rate law, in turn equilibrating with C, also with first order kinetics. The associated thermodynamic and kinetic data are given in the equation shown: E. - 40 kcal mort E = 20 kcal mort А AG* = 0 kcal molt AG* +0 kcal mor! a. Complete the energy diagram below as follows: 1. Starting with A positioned at level "O" (black bar), indicate the respective positions of B and C along the reaction coordinate (use bars and label them with the respective letters), 2. Show the positions of the two respective transition states (bars) that reflect the activation energies of the two steps. Label them TSAB and TSBC", respectively, Potential-Energy Diagram A B с 40 20 А. O -20 40 E (kcal mol-1) Reaction coordinate
9 b. You can monitor the progress of the equilibrations. Place an "X" mark in the box next to the correct statements below (there may be several). A disappears at the same rate at which B+C appears. B converts to C faster than back to A. At full equilibration, the ratio of A:B:C is 1:1:1. In the initial stages of the transformation of A, one can observe a build-up of TSAB The conversion of A follows the rate law: Rate = K[A].