What is the standard change in free energy (in kJ) at 148°C for the reaction below, given ∆H° = -219 kJ and ∆S° = +21.7
Posted: Mon May 16, 2022 10:27 pm
What is the standard change in free energy (in kJ) at 148°C for
the reaction below, given ∆H° = -219 kJ and ∆S° = +21.7 J/K at
25°C?
2 MO2(g) → 2 MO(g) + O2(g)
the reaction below, given ∆H° = -219 kJ and ∆S° = +21.7 J/K at
25°C?
2 MO2(g) → 2 MO(g) + O2(g)