can someone explain to me how we found 0.37 in solution . Also, How we find 6.2*10^8.
Posted: Mon May 16, 2022 9:40 pm
can someone explain to me how we found 0.37 in solution . Also, How we find 6.2*10^8.
LE . 11:59 Answer 1 of 1 Done mnoles of righe concertention some - 1 tỷ ý k vl Sweet Males 4 EDTA: Lentilshow reclume My 5 Since, Migl 4 Myhume GESTA Counds ho fa uns PN Mga EDTAM I 5 c E kp [mg) Inngas tam RJ PM 10 37 kg : 42 (o (3) DU- 2.294 2.354 d. 07: on solving quadratic equation, we get * [mg").im ping leg (ongeng - 36 werd ontwez eption 814.75
can you write the steps for Q. II 10)CLO-6) Calculate the pMg in the reaction of 50 mL of 0.1 M Mg(buffered to pH 10) with 25 mL of 0.2 MEDTA Mg + EDTA -- MgY2 K-2.2 x 10 A)3.75 B)4.75 C)4.97 D)5.32 E)4.25
- Can Someone Explain To Me How We Found 0 37 In Solution Also How We Find 6 2 10 8 1 (20.65 KiB) Viewed 61 times
- Can Someone Explain To Me How We Found 0 37 In Solution Also How We Find 6 2 10 8 2 (20.65 KiB) Viewed 61 times
- Can Someone Explain To Me How We Found 0 37 In Solution Also How We Find 6 2 10 8 3 (12.67 KiB) Viewed 61 times
can you write the steps for Q. II 10)CLO-6) Calculate the pMg in the reaction of 50 mL of 0.1 M Mg(buffered to pH 10) with 25 mL of 0.2 MEDTA Mg + EDTA -- MgY2 K-2.2 x 10 A)3.75 B)4.75 C)4.97 D)5.32 E)4.25