Answer Happy

An ideal solenoid of length l=1m and turn density n=10 turns/cm
carries a current I that decreases at a constant rate of 3 mA/s
starting at 4A. Inside the solenoid there is a copper wire ring of
radius a=3 cm whose plane makes an angle β=20 degrees with the axis
of the solenoid. Write an expression for the induced emf in the
ring as a function of time, and calculate the induced current
knowing that the thickness of the ring in 2 mm. Follow the steps
below : a)Write an expression for I as a function of time; b) using
the result in a), write an expression for B solenoid as a function
of time; c) Using the result in b) and the definition of the flux,
write an expression for the flux through the copper ring as a
function of time;be careful with the angle d) Plug in the
expression for flux into Faraday’s Law to find induced emf e) to
find the current use Ohm’s Law i=voltage/resistance; use the
resistivity of the copper and the length/cross sectional area of
the wire ring to find its resistance.