Answer Happy

An ideal solenoid of length l=1m and turn density n=10 turns/cm
carries a current I that decreases at a constant rate of 3 mA/s
starting at 4A. Inside the solenoid there is a copper wire ring of
radius a=3 cm whose plane makes an angle β=20 degrees with the axis
of the solenoid. Write an expression for the induced emf in the
ring as a function of time, and calculate the induced current
knowing that the thickness of the ring in 2 mm.
Follow the steps below :
a)Write an expression for I as a function of time;
b) using the result in a), write an expression for Bsolenoid as
a function of time;
c) Using the result in b) and the definition of the flux, write
an expression for the flux through the copper ring as a function of
time;be careful with the angle
d) Plug in the expression for flux into Faraday’s Law to find
induced emf
e) to find the current use Ohm’s Law i=voltage/resistance; use
the resistivity of the copper and the length/cross sectional area
of the wire ring to find its resistance.