A simple harmonic oscillator's acceleration is given by ay(t) = (0.810 m/s2)cos(11.00 – 5.85). Find the oscillator's pos
Posted: Mon May 16, 2022 6:20 pm
A simple harmonic oscillator's acceleration is given by ay(t) = (0.810 m/s2)cos(11.00 – 5.85). Find the oscillator's position, velocity, and acceleration at each of the following times. (Include the sign of the value in your answer.) (a) t = 0 0.735 position X The response you submitted has the wrong sign. m -3.7400 x velocity The response you submitted has the wrong sign. m/s -88.9571 x acceleration The response you submitted has the wrong sign. m/s2 (b) t = 0.500 5 0.7609 position x The response you submitted has the wrong sign. m 3.0552 x velocity The response you submitted has the wrong sign. m/s -91.0679 X acceleration The response you submitted has the wrong sign. m/s2 (c) t = 2.00 s -7.3214 x position The response you submitted has the wrong sign. m 3.811 x velocity The response you submitted has the wrong sign. m/s 88.5895 x acceleration The response you submitted has the wrong sign. m/s2