Answer Happy

Posted: **Mon May 16, 2022 4:01 pm**

: 3 C G H M N 0 0 0 10 13 16 5 21 26 5 Graph 1 Graph 2 1 E Ze 120 Y 10 10 14 100 44 5 52 30 43 03 60 Poutin Position 40 V 1 (27.37 KiB) Viewed 33 times

: 3 C G H M N 0 0 0 10 13 16 5 21 26 5 Graph 1 Graph 2 1 E Ze 120 Y 10 10 14 100 44 5 52 30 43 03 60 Poutin Position 40 V 2 (45.14 KiB) Viewed 33 times

: 3 C G H M N 0 0 0 10 13 16 5 21 26 5 Graph 1 Graph 2 1 E Ze 120 Y 10 10 14 100 44 5 52 30 43 03 60 Poutin Position 40 V 3 (45.14 KiB) Viewed 33 times

3 c G H M N 0 0 0 10 13 16.5 21 26.5 Graph 1 Graph 2 1. E ZE 120 Y-10-10 14 100 44.5 52 30 43 03 60 Poutin Position 40 VO 34 30 ro 68.5 77.5 87 57 10 119.5 O SO 1 ST CE 3 4 0 0 TE 35 3 3 Time CE . STET 1 SC 2 25 0.972 1.139 1.26 1.162 1.416 1412 1412 1356 1.205 1.19 SC 25 3 25

1.Following are the two sets of position and time data collected using a motion sensor and cart. Time Position Vinstantaneous) (s) (m) (m/s) 0 10.0 0.25 13.0 0.50 16.5 0.75 21.0 1.00 26.5 1.25 32.3 1.50 38.0 1.75 44.5 2.00 52.0 2.25 60.0 2.50 68.5 2.75 77.5 3.00 87.0 3.25 97.0 3.50 108.0 119.5 4.00 131.5 Time (8) 1 1.25 1.5 1.75 2 2.25 2.5 2.75 3 3.25 3.5 Position V(instantaneous) (m) (m/s) 0.972 1.139 1.269 1.362 1.416 1.432 1.412 1.356 1.265 1.139 0.979 3.75 V=Xa-X1 ta-ti Table 2 Table 1