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The questions weral part that must be comited. If you so part of the question ou will not be my paint for the speed art, and you will not be able to come back to med at Tutorial Exercise At an outdoor market, a bunch of bananas attached to the bottom of a vertical spring of force constant 160 Nm is set to story motion with an amaitude of 20.0 com.tr that the maximum speed of the bunch of bananas 44.1 Vs What is the weight of the bananas in newtons? Step 1 The bunch of bananas has maximum speed aut paste through the equilibrium position, where the last potential energy tored in the springer. When the bunch of bananas at maximum displacement from the ultrum position, it is momentanly at rest with speed. Since the type of force described by Hooke's law that is exerted on the bunch of bananas by the spring is a conservative force, the total mechanical energy of the spring-bananas system is constant. Let me, and E, denotthew and finelinetic energies of the Duch of bananas, and it and Pedence the initial and final potential energies of the banana-spring system. Applying conservation of energy to the interval between the systeme equilibrium position and its position at maximum displacement from equilibrium gives KEPE-KE, PE Let var denote the speed of the bunch of bananas at maximum displacement, the amplitude, m the mass of the bananas, and the force constant or the spring. Then, the conservation or energy equation becomes 2.00 ma Solving for the mass of the bunch of bananas, we have (16.0 Nm) kg with the weight of the bunch of bananas as - mg ka) (9,80 m/=) - N Samal