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Monochromatic light of wavelength 1 is incident on a pair of slits separated by 2.15 x 10-4 m and forms an interference

Posted: Mon May 16, 2022 3:14 pm
by answerhappygod
Monochromatic Light Of Wavelength 1 Is Incident On A Pair Of Slits Separated By 2 15 X 10 4 M And Forms An Interference 1
Monochromatic Light Of Wavelength 1 Is Incident On A Pair Of Slits Separated By 2 15 X 10 4 M And Forms An Interference 1 (35.71 KiB) Viewed 58 times
Monochromatic light of wavelength 1 is incident on a pair of slits separated by 2.15 x 10-4 m and forms an interference pattern on a screen placed 2.15 m from the slits. The first-order bright fringe is at a position Ypright = 4.56 mm measured from the center of the central maximum. From this information, we wish to predict where the fringe for n = 50 would be located. (a) Assuming the fringes are laid out linearly along the screen, find the position of the n = 50 fringe by multiplying the position of the n = 1 fringe by 50.0. 0.23 ✓m .(b) Find the tangent of the angle the first-order bright fringe makes with respect to the line extending from the point midway between the slits to the center of the central maximum. Enter a number. differs from the correct answer by more than 100%. (c) Using the result of part (b) and dsin bright = ma, calculate the wavelength of the light. 1x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. nm (d) Compute the angle for the 50th-order bright fringe from dsinê bright = mi. = (e) Find the position of the 50th-order bright fringe on the screen from Ybright = Ltan bright (f) Comment on the agreement between the answers to parts (a) and (e). This answer has not been graded yet Need Help? Read it