Topic 3 - How does a hot air balloon work? Part 1) A block of wood is observed to float in a pool of water. The top of t
Posted: Mon May 16, 2022 2:48 pm
Topic 3 - How does a hot air balloon work? Part 1) A block of wood is observed to float in a pool of water. The top of the block is dry. Which of the following statements are true? (Select all that are true) The volume of the block that is submerged equals the volume of the displaced water. The weight of the block is equal to the weight of the displaced water. The weight of the displaced water is greater than the weight of the block. The density of the water is the same as the density of the block. The buoyancy force is greater than the weight force. Part 2) The block of wood displaces Vwater = 0.79 m² of water and Vwater= 87 % (given to two significant figures) of the block is submerged. In Vwood this expression Vwood is the volume of the block of wood in m?
Part 2) The block of wood displaces Vwater = 0.79 m² of water and Vwater= 87% (given to two significant figures) of the block is submerged. In this expression Vwood is the volume of the block of wood in m? Vwood Volume of block above water Volume of submerged block What is the density of the block of wood? Assume the density of fresh water is 1000 kg/m² Pwood = kg/m3 Part 3 m If the block of wood is now floated in seawater (density = 1025 kg/mº), what percentage of the block is now above the water? Percentage of wood block above the water's surface = %
Part 2) The block of wood displaces Vwater = 0.79 m² of water and Vwater= 87% (given to two significant figures) of the block is submerged. In this expression Vwood is the volume of the block of wood in m? Vwood Volume of block above water Volume of submerged block What is the density of the block of wood? Assume the density of fresh water is 1000 kg/m² Pwood = kg/m3 Part 3 m If the block of wood is now floated in seawater (density = 1025 kg/mº), what percentage of the block is now above the water? Percentage of wood block above the water's surface = %