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Refer to the galvanic cell below (the contents of each half-cell are written beneath each compartment): Ni 1.0 M N2 1,0

Posted: Tue Nov 16, 2021 6:27 am
by answerhappygod
Refer To The Galvanic Cell Below The Contents Of Each Half Cell Are Written Beneath Each Compartment Ni 1 0 M N2 1 0 1
Refer To The Galvanic Cell Below The Contents Of Each Half Cell Are Written Beneath Each Compartment Ni 1 0 M N2 1 0 1 (33.15 KiB) Viewed 62 times
Refer To The Galvanic Cell Below The Contents Of Each Half Cell Are Written Beneath Each Compartment Ni 1 0 M N2 1 0 2
Refer To The Galvanic Cell Below The Contents Of Each Half Cell Are Written Beneath Each Compartment Ni 1 0 M N2 1 0 2 (15.98 KiB) Viewed 62 times
Refer To The Galvanic Cell Below The Contents Of Each Half Cell Are Written Beneath Each Compartment Ni 1 0 M N2 1 0 3
Refer To The Galvanic Cell Below The Contents Of Each Half Cell Are Written Beneath Each Compartment Ni 1 0 M N2 1 0 3 (16.3 KiB) Viewed 62 times
Refer to the galvanic cell below (the contents of each half-cell are written beneath each compartment): Ni 1.0 M N2 1,0 M AG The standard reduction potentials are as follow: Ni2+2 e Ni(s), E =-0.26 Ag* + e → Ag(s), E = 0.7996 When current is allowed to flow, which species is reduced? Select one: a. Cannot be determined from the data given b. NI OC Ag d. Ag e. N12
If a redox reaction occured with the 2 redox couples provided below, which species would be the reducing agent? Pb2+ (aq) + 2e → Pb(s) E-0.13 V 4H+ (aq) + MnO2 (s) + 2e → 2H20 (1) + Mn?(aq) E = 1.23 V Oa. Mn?"(aq) Ob. Pb(s) Oc. Pb(a Od. Mnois) Ce. H2001)
Two half-reactions are shown with their standard cell potentials. If a galvanic cell is constructed using them, which electrode would be the anode, and what would the cell potential be? Ca2+ (aq) + 2e + Ca(s); Ex-0.40 V Fe2(aq) + 2e → Fe(s); E=-0.44 V Ca. Cadmium, -0.04 V Ob. Cadmium, 0.84 V c. Iron, 0.04 V Od, Cadmium, 0.04 V Oe. Iron, -0.04 V