Answer Happy

Experiment 7 Xanthine oxidase with allopurinol-IC50 Student number: : Student name: Section: Objectives; Results: Fill in the table below manually or using excel. Well no. 1 2 3 4 5 6 7 8 9 Phosphate 150l 1451 95 l l أبر 95 95 l 95 95 95 951 50 l 50 l 50 l 50 W 50 SO Soul Soul soul Buffer Xanthine substrate (0.6mM Allopurinol -- 50 50 SO 50 50! Soul soul 40ng/ml 400ng/ml 2ua/ml 4p/ml 40g/ml 200/ml 400g/ml sul 5ul 5 Sul 5 Sul 5ul 5 l Xanthine oxidase enzyme Zero Final concentration of allopurinol per well (g/ml) Absorbance (30 minutes) inhibition 1. Calculate the final concentration of allopurinol per well (kg/ml). Stock concentration - 40ng/ml - 400ng/ml 2mg/ml
Experiment 7 Xanthine oxidase with allopurinol-C50 Student name Student number Section: Objectives: Results: Fall in the table below manually or using excel 1 2 3 5 7 150 145 95 95 Buster th 95 SO 50 SO 50 50 05 Ano Soul 50 SO SO SO Ong/ml 400ng/m 2 / 40/200,00 5 3. Su 5 5 5 ze Alloc centration 0.5 Absorbante 30 tes ♡ 1009 oool 1 10 50 100 2.7881.045 Lell6 1.099 1.0471,028 & 975 01951 6.959 27.-21.0 -1.776.6127.2336.57 33.46 62651 117% 82% 48% 74% 58%. nition 33 1. Calculate the final concentration of allopurinol per well g/ml). Stock concentration 40ng/ml = 40X163 x 50 = M2 x 200 M2: rool 2 x 400 x 10 x 50 = M2 x 200 M₂ = 0.1 300ng/mi 2/mi 2 x 50 - Me x 200 M2 = 20.5 Aug/mi 4x50 M r 1200 Me=1