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5. Earth whose in situ weight is 125 lb/cf and whose compacted weight is 120 lb/cf is placed in a fill at the rate of 26

Posted: Mon May 16, 2022 12:33 pm
by answerhappygod
5 Earth Whose In Situ Weight Is 125 Lb Cf And Whose Compacted Weight Is 120 Lb Cf Is Placed In A Fill At The Rate Of 26 1
5 Earth Whose In Situ Weight Is 125 Lb Cf And Whose Compacted Weight Is 120 Lb Cf Is Placed In A Fill At The Rate Of 26 1 (18.47 KiB) Viewed 45 times
5 Earth Whose In Situ Weight Is 125 Lb Cf And Whose Compacted Weight Is 120 Lb Cf Is Placed In A Fill At The Rate Of 26 2
5 Earth Whose In Situ Weight Is 125 Lb Cf And Whose Compacted Weight Is 120 Lb Cf Is Placed In A Fill At The Rate Of 26 2 (37.84 KiB) Viewed 45 times
5 Earth Whose In Situ Weight Is 125 Lb Cf And Whose Compacted Weight Is 120 Lb Cf Is Placed In A Fill At The Rate Of 26 3
5 Earth Whose In Situ Weight Is 125 Lb Cf And Whose Compacted Weight Is 120 Lb Cf Is Placed In A Fill At The Rate Of 26 3 (37.84 KiB) Viewed 45 times
5. Earth whose in situ weight is 125 lb/cf and whose compacted weight is 120 lb/cf is placed in a fill at the rate of 265 cy/hr, measured as compacted earth. The thickness of compacted layers is 8 in. A roller having a drum width of 50 in operates at a speed of 3 mph. Assume a 50-min. hour operating efficiency. Determine the number of rollers required to provide the necessary compaction if 5 passes are specified for each layer of earth.
5. Earth whose in situ weight is 125 lb/cf and whose compacted weight is 120 lb/cf is placed in a fill at the rate of 265 cy/hr, measured as compacted earth. The thickness of compacted layers is 8 in. A roller having a drum width of 50 in operates at a speed of 3 mph. Assume a 50-min. hour operating efficiency. Determine the number of rollers required to provide the necessary compaction if 5 passes are specified for each layer of earth. AREA = 2605 YdB/HR 2000* 27042/H 7155 FPIHR x 12 in 16 > 10732.5 6+214 Bin REU PASSES = 107325 * 5 - 5300254 ihr AVO SPEED. SPEED - 3 mph * 6280441mi - 15840 FI HR COVERED AREA * 15840 x (52) (SO) = 55,000 4+1 δΈͺ WIDTH OF DEUM - SOIN X 12 NUMBER OF ROLLERS = REQ + OF ROLLERS = ReQ. PASSES COVERED ALEA - 0.98 I RULLER 536062.5 *+/HR 55000 FH