USE THE CLASS PROBLEM ARCHE FOR X-Oto 15 T, USE 0.5 FT INCREMENTS SHOW VALUES for Y. DERECTION • You NAVE A ESUATU for o
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EN 137 RSAP اور 19.13 W/4* 30 Handbank 7.291 in E 29-10p Ts 15 R-23-93 Rs.657 M-O-3573) B-6667 je مالی و C- 0<x5' "52x215 + ** M = 0 - 299X-M 2218-M out M 23.593x Soome 23.mxos, o Soy 23:02x+5x+3 275) Cuz EMaut - 203>>x - 35(x-3) - M 25 (-5) 227x - 3$(x-3)*+63 ME 29 333 - - Soy 32-678)*****C4 وتے۔ 2 19.13 . 23.013 (15) * - $ (15-5)=G(3) 4C * at pt. C when x-5 Yo 40 Ss 23,028 x ts, *px 3555**cs **** dollections mos X 21.328XCX = 23 Proteske guance DALA 16-07 אז מה
ہوتے۔ 4.13 Oo. Znang (15) *- * (5-5)=568) 4.Co at pt. c when xos 40 +6ampak 159)+cs deflectoris papeles que 4** slopes 000 24.869 TA XX BALIC Ta YO Cos, and Co O= - SHaxie Cylis) C = 2.0 le = whert X= 5 ya [upx-(400)x Zurzemes yo [ 136.104-3455 xv0*] 4:20 : compare to Table U- 398 M60 -. Sps ELASTIC CURVE V that turke RAY curie - 11.657 xels M 2539 23.99 5* 0<x<5 M-22373 X PA SM - 23 392*** Manto 2503 354-5) M = 2.333X - - 3567-5) 13568-5 C3
compare to Table. ELASTIC CORVE 170 equation thatowwe zuki RAY Š R = 11.6676 X रहे 23.33% XO - ? 1 ? 21383 23.3 + C-3 5x15 0<x<5 M-23333 + M = 23.335x - 35(4-5) -55 • 235938 +Cx+C2 PSMS 2 00 + C4 PA-SM = 2339237C 38(2-5) => Proven golegama aml -3567-34-gx y=o=2373 (15)- 35. is-s) + 65)+44 unknowns a Cs and meca ? use another approach. PROVE 4 C2- 4 yo when X=15 G e ELASTIC CURVE 4 Ty=f(x) AC URIND THIS 02X45 $<x215 Common pt same delle tromy same slutpe o at Dame ye- P243 +6x=74 X=5 yo shi-s) + CX+ly 2333X - 7
use another approach. ELASTIC CURVE Ty=f(x) DEIND THIS CB SOTTON AC 0<x<5 <x<15 Comment same delle strony same slape, o at pame point x=50 92 .. -C,Xebel = 33 - 35k-$) +CX+ly , ScoPES AC when X=5 za usy +s, - 1992-2565)+c9 To, CE BACK 58 PROVES CO GO BACK TO E y CB y=when X=15 3 ܘܐܪ ) ته - دوو 22 -35 (x+3)+csxtfie 23:33 (3) - 35 «s-s) + Ca(5) (15- Souve = - 486.111 Cy= .. Between A anec, 0<x45' 3 4- 23.933"po x + (- 481.1) ET EI Х for any f Value of x from 05 radius of curvature DMS curvature = array 12 J Hable. } TLM FE
O Selve CE-486.111 C3C, an 6 of 9 tween A and C, os x <5' K ® 4-1 23.933"ps X'+ (- 48. m) ET ΕΙ 5 Jor | ots' any Value of x from le radius of curvature FDMS ė *2 EI FE Curature [31*** ) Adbok. ay- -variable dx Constant ē vertete - CEI M e dy & S • San SSM - •put back Beam W14 x 30 STEEL TABLES Ixx = 291 STEEL, E- 29x101 E- 510 (29uoks, y 29 m3= 8.439x0?b-in - 2980. / M-force x dist= kips ft SM = 10%-ft - - your 10316-4 SSM ISM = 1016 ca
Beam W14 * 30 STEEL TABLES Inox = 291 in STREL, E = 29x1064 EI - 29x10 x (2 / 291 m3 28.459x8?u- M = force x dist= kips ft 10 lb-ft SM = 10²6-ft SSM SSM = 1016 = - BYTTE 10%-k x/2 in (y 12612x121728 converter ya - 486.11 x 1728 30 [0<x<5 whenX=5' find y Solve y=-391./10 Very Small Factor X Yo [ 23.933 for any O< X X values y = 1-0.394 %-4 yo O'< x <5 IF use x+ EI yo 20037 $'=(- 40.4)7] . I= (2941041 / 291 in) -8.459.jpg ( 8.4393409 Ib- Sx= feet ( (10316) 6) ft (124) 16-in- *12*12-17224
for any x values X find y wher-X-5 Solve y=-391.196103 y = 1/-0-598-4 y IF w O'< x 25 y g [22:03 x'+(-40.1)= = =(29-10-an,/ 291 in) - 8.4 (291 in) -8.459yo? EIE 8.439x10 b-m² Sx= feet (103) ft 116-in- 12*12*12= 1728 मा lb (124) este un any を選 ET 1036 [22 323 – 481.11 XXX 1728 x 8.499412 عال 3 when (x=5] x] -398.146x 10 in = -0.398 xEootench use eg 4 5'< X 215 ya appox'- 15(x-3)+(- 44iyx General ET-7.43980 "Curve under point So when x=5 loda sub. in Values for 17/ Gez x1728 for Elastic Baguetien
(10²16) ft 16-in 12 X 12x12-17284 (+03 pt x1036 17280 - U= 23.33 9 of 9 ayor Jo SM ЕТ 486.111 X X 8.429 when (x=57 ] - 398.146* 10 = 0.398 x Cootench use eg. 6 5'< x 215 1106 to panxa 15(603)+(-tex babes General * 1723 ET 2.439x " (Equation Facurve ation for Elastic under point loda So when X=5' suto in Values for 17/5 Geg Excel 6.5 Type in équation 6 under 15 Column forg for final exam credit & * Deflection ander point load 6 WHERE is man deflection WHAT is that may deflection AL