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The truss structure shown below is pinned to the wall at E and F h h h h + + H G F h A B C D e W Allow W=445 kN h=3.5 m

Posted: Mon May 16, 2022 6:28 am
by answerhappygod
The Truss Structure Shown Below Is Pinned To The Wall At E And F H H H H H G F H A B C D E W Allow W 445 Kn H 3 5 M 1
The Truss Structure Shown Below Is Pinned To The Wall At E And F H H H H H G F H A B C D E W Allow W 445 Kn H 3 5 M 1 (133.03 KiB) Viewed 84 times
The Truss Structure Shown Below Is Pinned To The Wall At E And F H H H H H G F H A B C D E W Allow W 445 Kn H 3 5 M 2
The Truss Structure Shown Below Is Pinned To The Wall At E And F H H H H H G F H A B C D E W Allow W 445 Kn H 3 5 M 2 (102.37 KiB) Viewed 84 times
The Truss Structure Shown Below Is Pinned To The Wall At E And F H H H H H G F H A B C D E W Allow W 445 Kn H 3 5 M 3
The Truss Structure Shown Below Is Pinned To The Wall At E And F H H H H H G F H A B C D E W Allow W 445 Kn H 3 5 M 3 (230.34 KiB) Viewed 84 times
The Truss Structure Shown Below Is Pinned To The Wall At E And F H H H H H G F H A B C D E W Allow W 445 Kn H 3 5 M 4
The Truss Structure Shown Below Is Pinned To The Wall At E And F H H H H H G F H A B C D E W Allow W 445 Kn H 3 5 M 4 (127.94 KiB) Viewed 84 times
The Truss Structure Shown Below Is Pinned To The Wall At E And F H H H H H G F H A B C D E W Allow W 445 Kn H 3 5 M 5
The Truss Structure Shown Below Is Pinned To The Wall At E And F H H H H H G F H A B C D E W Allow W 445 Kn H 3 5 M 5 (142.24 KiB) Viewed 84 times
please help thanks
The truss structure shown below is pinned to the wall at E and F h h h h + + H G F h A B C D e W Allow W=445 kN h=3.5 m 052.1 degrees
Part A - Part A Is this structure statically determinate? Yes Ο Νο Submit Request Answer Part B - Part B Identify any zero force members, More than one option may be selected. O Member AB O Member AJ O Member BC O Member BH J Member BJ O Member CD Member CG Member CH O Member DE
Member CG Member CH Member DE Member DF > Member DG Member EF Member FG O Member GH O Member GJ Submit Request Answer Part C - Part C You are asked to find the forees in members GH and CG using the Method of Sections. Which members should you make a cut through? More than one option may be selected. 20 Member AB Member AJ Member BC Member BH Member BJ
Having made a cut through the members in the previous part, you next want to solve for Member GH. Which of the following equilibrium equations is the most efficient? (ie which one will allow you to solve for the Tequired member in one equation?) ΣΜΗ = 0 Ο ΣF, = 0 O SF, = 0 O SMC=0 Ο ΣΜ = 0 Submit Request Answer Part E - Part Solve for the force in member GH and state whether it is in tension or compression Express your answer to three significant figures in units of lN. Enter negative value in the case of compression and positive value in the case of tension. Fch = 89 D EN Previous Answers Correct
Part G - Part 6 Next we want to solve for the force in Member DE What would be the most efficient approach to solving for the force in this member? O Using Method of Joints O Using Method of Sections and then IMD=0 Using Method of Sections and then SF, = 0 O Using Method of Sections and then SME = 0 Using Method of Sections and then IF, = 0 W Q Using Method of Sections and then Mp=0 Submit Request Answer