A = -2i – j + 5k B = 3i + 3j – 2k C = -5i – 2j – 4k 2. A solid rod of steel (E = 200 GPa) is 100 cm in length and has a
Posted: Mon May 16, 2022 6:17 am
A =
-2i – j + 5k
B =
3i + 3j – 2k
C =
-5i – 2j –
4k
2. A solid rod of steel (E = 200 GPa) is 100 cm in length
and has a cross section of 3 mm x 5 mm. The rod is subjected
to an axial tensile force of 10 kN. Find the normal stress,
the train and the axial deformation of the rod. (10
points)
-2i – j + 5k
B =
3i + 3j – 2k
C =
-5i – 2j –
4k
2. A solid rod of steel (E = 200 GPa) is 100 cm in length
and has a cross section of 3 mm x 5 mm. The rod is subjected
to an axial tensile force of 10 kN. Find the normal stress,
the train and the axial deformation of the rod. (10
points)