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. (20 points) For the linkage shown below, the link lengths Z A = 11,|AB| = 23 m. At the configuration shown, the angles
Posted: Sun May 15, 2022 11:58 pm
by answerhappygod
- 20 Points For The Linkage Shown Below The Link Lengths Z A 11 Ab 23 M At The Configuration Shown The Angles 1 (23.66 KiB) Viewed 44 times
- 20 Points For The Linkage Shown Below The Link Lengths Z A 11 Ab 23 M At The Configuration Shown The Angles 2 (30.12 KiB) Viewed 44 times
. (20 points) For the linkage shown below, the link lengths Z A = 11,|AB| = 23 m. At the configuration shown, the angles ZBZA = 60°, ZABZ = 24.268°. If the crank rotates with an angular velocity of 1 rad/s, and the force at point P is 10 N, the power due to inertial forces is 142.8 Nm/s, the power due to inertial torques is -225.70 Nm/s (note the negative sign, which is ok as it implies that the force/torque is applied in the direction opposite to the movement of the link; here it means that the link is rotating in a direction opposite to the angular acceleration). Specify the torque in Nm on a motor (up to 2 decimal places without units) required to drive the linkage at this position.
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