Answer Happy

The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle. Constant pressure heat addition 4 3 PVY = constant Heat IN Pressure (P) Adiabatic expansion 2 5 Heat OUT (Constant volume heat rejection) Constant volume heat addition Adiabatic compression Volume (V) Using the Dual Air Standard Cycle and the following data: Assume constant properties of air. R = 287 J/kgK; Cp = 1005 J/kgK; CV = 718 J/kgK; y = 1.4 • Cycle compression ratio = 14 (v1/v2) • Air conditions prior to compression: Pressure = 1.2 bar; Temperature = 285K • Heat added at constant volume = 290000 J/kg Heat added at constant pressure = 770000 J/kg
) a) Calculate the pressure at the end of the compression process. P2 = bar Submit part 2 marks Unanswered b) Calculate the temperature at the end of the compression process. T2 = K Submit part 2 marks Unanswered c) Calculate the temperature at the end of the constant volume heat addition process. T3 = K
d) Calculate the maximum cycle pressure. Pax = bar Submit part 2 marks Unanswered e) Calculate the maximum cycle temperature. Tmax = к Submit part 2 marks Unanswered f) Calulate the temperature at point 5. T5 = K
g) Calculate the pressure at point 5. P5 = bar Submit part 2 marks Unanswered h) Calculate the cycle efficiency as a percentage. n = %