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The shown plots are the solutions of velocity profiles (left) and temperature profiles (right) for the free convection b

Posted: Sun May 15, 2022 11:05 pm
by answerhappygod
The shown plots are the solutions of velocity profiles (left)
and temperature profiles (right) for the free convection boundary
layer condition on an isothermal, vertical surface under laminar
flow condition. (a) Please explain the physical meaning of y-axis
and (b) why the curves converge at about 5-6 for velocity (left
figure) for Pr ≤ 0.72 while temperatures (right figure) do not have
the trend? (c) Considering this vertical plate is 1 meter long at a
uniform temperature of 100 oC. The plate is suspended in quiescent
air that is 20 oC. Please calculate the velocity of boundary layer
thickness and maximum upward velocity at middle of the plate.
PROPERTIES: Air (Tf=323K): =18x10-6 kg/s‧m, Pr=0.7
The Shown Plots Are The Solutions Of Velocity Profiles Left And Temperature Profiles Right For The Free Convection B 1
The Shown Plots Are The Solutions Of Velocity Profiles Left And Temperature Profiles Right For The Free Convection B 1 (366.29 KiB) Viewed 26 times
03 0.21 0.6 Pr-0.01 . 0.1 0.4 0 6 8 10 12 14 16 18 20 22 24 Pr -0.01 0.2 0.7 0 6 8 10 12 14 16 18 20 22 0.6 Pr -0.01 1.0 21 0.5 Pr-0.01 0.4 0.8 PROBLEM 4 (15 points, 2.5 points for a and b and 10 for c) The shown plots are the solutions of velocity profiles (left) and temperature profiles (right) for the free convection boundary layer condition on isothermal, vertical surface under laminar flow condition. (a) Please explain the physical meaning of y-axis and (b) why the curves converge at about 5-6 for velocity (left figure) for Pr <0.72 while temperatures (right figure) do not have the trend? (c) Considering this vertical plate is 1 meter long at a 0 1 2 3 4 5 6 7 uniform temperature of 100 °C. The GO plate is suspended in quiescent air that is 20 °C. Please calculate the velocity of boundary layer thickness and maximum upward velocity at middle of the plate. PROPERTIES: Air (T323K): v=18x10 kg/s-m, Pr=0.7 l'on) - Gr" 2v 0.72 0.3 0.6 0.72 1 2 10 100 r1000 T =(T-T/T,-TD 0.2 0.4 2 10 100 1000 0.1 0.2 0 5 6 1 2 3 (Gr Gr" no (a)