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Part B: 10 marks The pipe network runs between two tanks (k for pipe entry of 0.2 and exit 1) over a distance of 25 m, w

Posted: Sun May 15, 2022 9:52 pm
by answerhappygod
Part B 10 Marks The Pipe Network Runs Between Two Tanks K For Pipe Entry Of 0 2 And Exit 1 Over A Distance Of 25 M W 1
Part B 10 Marks The Pipe Network Runs Between Two Tanks K For Pipe Entry Of 0 2 And Exit 1 Over A Distance Of 25 M W 1 (85.33 KiB) Viewed 55 times
Part B 10 Marks The Pipe Network Runs Between Two Tanks K For Pipe Entry Of 0 2 And Exit 1 Over A Distance Of 25 M W 2
Part B 10 Marks The Pipe Network Runs Between Two Tanks K For Pipe Entry Of 0 2 And Exit 1 Over A Distance Of 25 M W 2 (50.21 KiB) Viewed 55 times
Part B 10 Marks The Pipe Network Runs Between Two Tanks K For Pipe Entry Of 0 2 And Exit 1 Over A Distance Of 25 M W 3
Part B 10 Marks The Pipe Network Runs Between Two Tanks K For Pipe Entry Of 0 2 And Exit 1 Over A Distance Of 25 M W 3 (1.21 MiB) Viewed 55 times
PLEASE SOLVE THIS IMMEDIATELY AND ALSO STEP BY STEP
SOLUTION WITH CORRECT ANSWERS REQUIRED. IF DONE SO WELL, DEFINATELY
A THUMBS UP AND PERFECT FEEDBACK WILL BE GIVEN.
Part B: 10 marks The pipe network runs between two tanks (k for pipe entry of 0.2 and exit 1) over a distance of 25 m, with a total static lift of 10 m between the two tanks. This pipe network includes two long sweeping elbows, a Mitre bend and a gate valve (1/4 open). Calculate: iii) the total head loss [7] iv) the hydraulic output required to pump the mixture between the two tanks [3] Part C: 12 marks The valve position in part B is changed, reducing the mass flow rate to 25 kg/s and the power output changes to 3.7 kW's. Determine, the new operating conditions (velocity, friction factor, hydraulic head, etc.). Then determine, to the nearest quarter, the new valve position of the gate valve. The following equations are given, as well as table 1:1 for the equivalent lengths of pipe and a moody diagram overleaf with the friction factor equation.
Thus head loss for turbulent flow is: foLU? Ah = 2gD Exit/Entry losses are: kv2 hexit 2g Hydraulic output: Reynold's number: pvd Re = Powerout = pg(h)Q и Table 1:1 Equivalent lengths of pipe for selected fittings 100mm diameter Gate valvefully open 0.8m Gate valve 1/4 closed 4.7 m Gate valvehalf closed 22 m Gate valve 3/4 closed 92 m T-piece - flow through run 2.1 m T-piece - flow through branch 8.5 m long sweeping elbow 2.1 m Mitre bend 5.2 m
0.1 0.09 0.08 Wholly turbulent flow 1.325 [In{(8/3.7D) + (5.74/ Re" 9)]]> 0.07 0.05 0.04 0.03 0.06 0.05 0.02 0.015 0.04 0.01 0.008 0.006 0.004 f 0.03 E D 0.025 0.002 0.02 Laminar flow 0.015 0.001 0.0008 0.0006 0.0004 0.0002 0.0001 0.00005 Smooth Transition range Laminar flow, f = 64/Reo 0.01 0.009 0.008 103 2(103) 4 6 8 2(104) 4 681 2(105) 4 68 2(106) 4 681 21107 4 6 8 0.00001 104 105 106 107 108 Rep = p.V.D/u
E 0.1 0.09 1.325 Wholly turbulent flow 0.08 In[(x/3.7D) + (5.74/Ref 0.07 0.05 0.04 0.06 0.03 0.05 0.02 0.015 0.04 0.01 0.008 0.006 0.03 0.004 D 0.025 0.002 0.02 0.001 0.0008 Laminar 0.0006 flow 0.015 0.0004 Smooth 0.0002 Transition range 0.0001 0.01 Laminar flow, t-64/Rey 0.00005 0.009 0.008 0.00001 2(10%) 4 6 8 2(104) 4 6 8 2(105) 4 681 2(106) 4 681 2(10%) 4 6 8 105 107 Re, A.V.D/ 103 104 106 108