Use the table ol - Cu → Cut Half-reaction TV) 2 (V] Half-reaction F. + 2 2F 2.870, + 2H2O + 4e - 40H 0.40 Ag? + 0.34 → A

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

Use the table ol - Cu → Cut Half-reaction TV) 2 (V] Half-reaction F. + 2 2F 2.870, + 2H2O + 4e - 40H 0.40 Ag? + 0.34 → A

Post by answerhappygod »

Use The Table Ol Cu Cut Half Reaction Tv 2 V Half Reaction F 2 2f 2 870 2h2o 4e 40h 0 40 Ag 0 34 A 1
Use The Table Ol Cu Cut Half Reaction Tv 2 V Half Reaction F 2 2f 2 870 2h2o 4e 40h 0 40 Ag 0 34 A 1 (50.83 KiB) Viewed 59 times
Use The Table Ol Cu Cut Half Reaction Tv 2 V Half Reaction F 2 2f 2 870 2h2o 4e 40h 0 40 Ag 0 34 A 2
Use The Table Ol Cu Cut Half Reaction Tv 2 V Half Reaction F 2 2f 2 870 2h2o 4e 40h 0 40 Ag 0 34 A 2 (37.11 KiB) Viewed 59 times
Use The Table Ol Cu Cut Half Reaction Tv 2 V Half Reaction F 2 2f 2 870 2h2o 4e 40h 0 40 Ag 0 34 A 3
Use The Table Ol Cu Cut Half Reaction Tv 2 V Half Reaction F 2 2f 2 870 2h2o 4e 40h 0 40 Ag 0 34 A 3 (40.63 KiB) Viewed 59 times
Use the table ol - Cu → Cut Half-reaction TV) 2 (V] Half-reaction F. + 2 2F 2.870, + 2H2O + 4e - 40H 0.40 Ag? + 0.34 → AB 1.99 Cu?+ + 2€ Conte Core 1.82 HgCl, + 2e → 2Hg + 2C 0.27 HO, + 2H*42c- 2H,0 1.78 AgCl + Ag + Cl 0.22 C + - Cell 1.70 SO.- + 4H+ + 2c 0.20 PbO, + 4H+ + SO,- + 2 PbSO + 2H,01.69 H,SO, + H2O MnO- + 4H+ + 3e MnO2 + 2H,0 1.68 Cu2+ + 0.16 10,- + 2H+ + 2e - 10, +H2O 1.60 2H+ + 2e H 0.00 MnO,- +8H+ + 5c - Mn2+ + 4H2O 1.51 Fe?+ + 3e - Fe -0.036 Au" + 3e Au 1.50 Pb+ + 2e - Pb --0.13 PbO, + 4H+ + 2c - Pb2+ + 2H2O 1.46 Sn2+ + 2e Sn -0.14 Cl2 + 20 21 1.36 Ni?+ + 2c - Ni -0.23 C20,2- + 14H+ +60 -2C++ + 7H.O 1.33 PbSO4 + 2e - Pb + S0,2- -0.35 O2 + 4H+ + 4c - 2H2O 1.2 Cd2+ + 2c> cd -0.40 MnO2 + 4H+ + 2 + Mn2+ + 2H,0 1.21 Fe2+ + 24 - Fe -0.44 10,- + 6H + 5c 112 + 3H20 1.20 Cr+ + e-C -0.50 Bra + 20 - 2B 1.09 C + + 3e-C -0.73 vo2H+ + - 1.00 Za2+ + 2c -0.76 Aucl. + 3e Au + 401 0.99 2H2O + 2 H2 + 2OH -0.83 NO, + 4H+ + 3c- NO + 2H,0 0.96 Mn2+ + 2e -1.18 Clo, te Clo, 0.954 AM" + 3c - Al -1.66 2Hg2+ + 2e - 0.91 H2 + 2c → 2H - 2.23 Ag +- As 0.80 Mg2+ + 2 Mg -2.37 + 2c 2Hg 0.80 La + 3c - La -2.32 FC + Fe+ 0.77 Na+ + " + Na -2.71 O, +2H+ + 2c -- HO 0.68 Ca?! + 20 Ca -2.76 MnO,- + - MOO 0.56 Ba2+ + 2c - Ba -2.90 1, + 2 21 0.54 K+ + - K Cut +- Cu -2.92 0.52 Lit te Li -3.05 Consider the following galvanic cell. vo?+ + H20 - Zn - Mn Hg." 2+ Hea (a)

pl (8) Consider the following galvanic cell. P pt Au- Pt pl pl pt of 1.0 M Au+ 1.0 M Cut 1.0 M Cu?+ of Choose the balanced equation for the reaction. Au(s) + 3 Cu2+ (aq) Auf (aq) + 3 Cut (aq) Au(s) Cu²+ (aq) + Aul+ (aq) + Cut (aq) Au + (aq) + Cut (aq) + Au(s) + Cu²+ (aq) Au' (aq) + 3 Cu* (aq) + Au(s) + 3 Cu²+ (aq) - - (b) Use the standard reduction potentials for the galvanic cell to determine E for the reaction in (a). (©). Consider the following galvanic cell. Cd- -PL
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply