How many grams of dipotassium succinate trihydrate (K2C4H4O4·3H2O, MW = 248.32 g/mol) must be added to 710.0 mL of a 0.0
Posted: Mon Nov 15, 2021 4:50 pm
How many grams of dipotassium succinate trihydrate
(K2C4H4O4·3H2O,
MW = 248.32 g/mol) must be added to 710.0 mL of
a 0.0564 M succinic acid solution to produce a pH
of 5.906? Succinic acid has
pKa values
of 4.207 (pKa1)
and 5.636 (pKa2).
How many grams of dipotassium succinate trihydrate (K2C4H404-3H2O, MW = 248.32 g/mol) must be added to 710.0 mL of a 0.0564 M succinic acid solution to produce a pH of 5.906? Succinic acid has pK, values of 4.207 (PK2]) and 5.636 (pK2). mass: en
(K2C4H4O4·3H2O,
MW = 248.32 g/mol) must be added to 710.0 mL of
a 0.0564 M succinic acid solution to produce a pH
of 5.906? Succinic acid has
pKa values
of 4.207 (pKa1)
and 5.636 (pKa2).
- How Many Grams Of Dipotassium Succinate Trihydrate K2c4h4o4 3h2o Mw 248 32 G Mol Must Be Added To 710 0 Ml Of A 0 0 1 (13.6 KiB) Viewed 94 times