Page 1 of 1

Given: M(C) = 12.01 g/mol; M(H) = 1.008 g/mol; M(Cl) = 35.45 g/mol; M(C2H5C1) = 64.51 g/mol. = = For the chemical compou

Posted: Mon Nov 15, 2021 4:47 pm
by answerhappygod
Given M C 12 01 G Mol M H 1 008 G Mol M Cl 35 45 G Mol M C2h5c1 64 51 G Mol For The Chemical Compou 1
Given M C 12 01 G Mol M H 1 008 G Mol M Cl 35 45 G Mol M C2h5c1 64 51 G Mol For The Chemical Compou 1 (45.75 KiB) Viewed 65 times
Given M C 12 01 G Mol M H 1 008 G Mol M Cl 35 45 G Mol M C2h5c1 64 51 G Mol For The Chemical Compou 2
Given M C 12 01 G Mol M H 1 008 G Mol M Cl 35 45 G Mol M C2h5c1 64 51 G Mol For The Chemical Compou 2 (26.61 KiB) Viewed 65 times
Given M C 12 01 G Mol M H 1 008 G Mol M Cl 35 45 G Mol M C2h5c1 64 51 G Mol For The Chemical Compou 3
Given M C 12 01 G Mol M H 1 008 G Mol M Cl 35 45 G Mol M C2h5c1 64 51 G Mol For The Chemical Compou 3 (33.34 KiB) Viewed 65 times
Given M C 12 01 G Mol M H 1 008 G Mol M Cl 35 45 G Mol M C2h5c1 64 51 G Mol For The Chemical Compou 4
Given M C 12 01 G Mol M H 1 008 G Mol M Cl 35 45 G Mol M C2h5c1 64 51 G Mol For The Chemical Compou 4 (32.28 KiB) Viewed 65 times
Given: M(C) = 12.01 g/mol; M(H) = 1.008 g/mol; M(Cl) = 35.45 g/mol; M(C2H5C1) = 64.51 g/mol. = = For the chemical compound C2H5C1: • (5 pts) The mass percent of carbon (C) is %. • (5 pts) The mass percent of hydrogen (H) is %. • (5 pts) The mass percent of chlorine (Cl) is %. • (5 pts) The mass of chlorine (Cl) in 50.0 grams C2H5Cl is

Question 4 Not yet answered Marked out of 5.00 P Flag question Consider the generic reaction 2 A + 3B → 2C Given 8.8 moles of A, calculate number of moles of C. a. 13.20 O b. 8.80 C. 5.87 O d. 4.40

Question 5 Not yet answered Marked out of 5.00 P Flag question One mole of Aluminum (Al) contains the same number of atoms as one mole of copper (Cu) Select one: True False

Question 6 Not yet answered Marked out of 5.00 Flag question Consider the generic complete reaction 2 A+ 3B → 2C Given 6.8 grams of A, calculate the mass in grams) of B (Hint: Molar mass of A is 44 g/mol. Molar mass of B is 18 g/mol). a. 4.17 O b. 1.85 O c. 8078.40 O d. 3590.40