= #1 – Common-Emitter Amplifier +15 V For the common-emitter amplifier shown to the left, the emitter resistor has resis
Posted: Sun May 15, 2022 5:38 pm
= #1 – Common-Emitter Amplifier +15 V For the common-emitter amplifier shown to the left, the emitter resistor has resistance Re = 1 k12, the collector resistance is Rc = 3 k12, and the BJT Rc has ß = 100, Vbe = 0,7 V. It is desired to have a base current ip = 40 uA. + (a) Find the emitter current ie. (b) Find the resistance RB + (c) Find the voltage across the BJT vce = RB VCE VBE 6 V + 1 RE CETTE ST