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CB1 RC Vtrap = -E Rc =266 +2E- Zc = 400 t=250 m Z 400 E' = -(2E) = (2E)=1.2 E Zc+ Rc 400+ 266 7 Ps = -0.2 Pe=1 0.25 -E 1
Posted: Sun May 15, 2022 3:23 pm
by answerhappygod
- Cb1 Rc Vtrap E Rc 266 2e Zc 400 T 250 M Z 400 E 2e 2e 1 2 E Zc Rc 400 266 7 Ps 0 2 Pe 1 0 25 E 1 1 (31.39 KiB) Viewed 34 times
CB1 RC Vtrap = -E Rc =266 +2E- Zc = 400 t=250 m Z 400 E' = -(2E) = (2E)=1.2 E Zc+ Rc 400+ 266 7 Ps = -0.2 Pe=1 0.25 -E 1.2E Ps Rc-zo 266-400 =-0.2 Rc+Zc 266+400 1.2E 1.4E V 1.16 E -0.24E 1.4E 1.016E 0.92 E 0.92E -0.24E 0.968 E T 31 ST 0.048E t 7.016E 0.048E -E Open end voltage waveform 33 Lattice Diagram Line transient