Answer Happy

This is my python code for a hang man game how do i add a gui
for the game to make it look nicer?
import random
def main():
welcome = ['This is Hangman. A random word will be chosen
and',
'you have to guess it letter by letter',
'be carful you only have so many chances before you lose. Good
Luck!'
]
for line in welcome:
print(line, sep='\n')
play_again = True
while play_again:
words = ["galaxy", "abruptly", "subway", "jukebox",
"dwarves",
"ivy", "peekaboo", "vaporize", "unknown", "glowworm",
"bagpipes", "joyful", "buzzwords", "buffoon", "luxury",
"frazzled", "megahertz", "topaz", "jaundice", "knapsack"
]
chosen_word = random.choice(words).lower()
player_guess = None
guessed_letters = []
word_guessed = []
for letter in chosen_word:
word_guessed.append("-")
joined_word = None
HANGMAN = (
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print(HANGMAN[0])
attempts = len(HANGMAN) - 1
while (attempts != 0 and "-" in word_guessed):
print(("\nYou only have {} attempts
remaining").format(attempts))
joined_word = "".join(word_guessed)
print(joined_word)
try:
player_guess = str(input("\nPlease select a letter between A-Z" +
"\n> ")).lower()
except:
print("That is not valid input. Please try again.")
continue
else:
if not player_guess.isalpha():
print("That is not a letter. Please try again.")
continue
elif len(player_guess) > 1:
print("That is more than one letter. Please try again.")
continue
elif player_guess in guessed_letters:
print("You have already guessed that letter. Please try
again.")
continue
else:
pass
guessed_letters.append(player_guess)
for letter in range(len(chosen_word)):
if player_guess == chosen_word[letter]:
word_guessed[letter] = player_guess
if player_guess not in chosen_word:
attempts -= 1
print(HANGMAN[(len(HANGMAN) - 1) - attempts])
if "-" not in word_guessed:
print(("\nGood Job! {} was the word").format(chosen_word))
else:
print(("\nTry Again! The word was {}.").format(chosen_word))
print("\nWould you like to play again?")
response = input("> ").lower()
if response not in ("yes", "y"):
play_again = False
if __name__ == "__main__":
main()