you are given an integer array nums with no duplicates. A maximum binary tree can be built recursively from nums using t
Posted: Sat May 14, 2022 3:33 pm
you are given an integer array nums with no duplicates. A
maximum binary tree can be built recursively from nums using the
following algorithm: Create a root node whose value is the maximum
value in nums. Recursively build the left subtree on the subarray
prefix to the left of the maximum value. Recursively build the
right subtree on the subarray suffix to the right of the maximum
value. Return the maximum binary tree built from nums. /** *
Definition for a binary tree node. * struct TreeNode { * int val; *
TreeNode *left; * TreeNode *right; * TreeNode() : val(0),
left(nullptr), right(nullptr) {} * TreeNode(int x) : val(x),
left(nullptr), right(nullptr) {} * TreeNode(int x, TreeNode *left,
TreeNode *right) : val(x), left(left), right(right) {} * }; */
class Solution { public: TreeNode*
constructMaximumBinaryTree(vector& nums) { } };
maximum binary tree can be built recursively from nums using the
following algorithm: Create a root node whose value is the maximum
value in nums. Recursively build the left subtree on the subarray
prefix to the left of the maximum value. Recursively build the
right subtree on the subarray suffix to the right of the maximum
value. Return the maximum binary tree built from nums. /** *
Definition for a binary tree node. * struct TreeNode { * int val; *
TreeNode *left; * TreeNode *right; * TreeNode() : val(0),
left(nullptr), right(nullptr) {} * TreeNode(int x) : val(x),
left(nullptr), right(nullptr) {} * TreeNode(int x, TreeNode *left,
TreeNode *right) : val(x), left(left), right(right) {} * }; */
class Solution { public: TreeNode*
constructMaximumBinaryTree(vector& nums) { } };