Answer Happy

Recall that "very satisfied" customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 62 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. (a) Letting u represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis He and the alternative hypothesis Hy needed if we wish to attempt to provide evidence supporting the claim that u exceeds 42. H0: μ 42 versus Ha:v 42 (b) The random sample of 62 satisfaction ratings yields a sample mean of c = 42.990. Assuming that o equals 2.69, use critical values to test Hy versus Ha at each of a = 10,05, 01, and 001. (Round your answer 2.05 to 3 decimal places and other z-scores to 2 darinallera!

(b) The random sample of 62 satisfaction ratings yields a sample mean of = 42.990. Assuming that o equals 2.69, use critical values to test Hy versus Ha at each of a = 10,05, 01, and 001. (Round your answer 2.05 to 3 decimal places and other z-scores to 2 decimal places.) za 2.90 Rejection Points 2.10 2.05 2.01 z. 001

Reject Ho with a = , but not with a = (c) Using the information in part (b), calculate the p-value and use it to test Ho versus Ha at each of a = 10, 05, 01, and .001. (Round your answers to 4 decimal places.) p-value = Since p-value = is less than reject HO at those levels of a but not with a =

(d) How much evidence is there that the mean composite satisfaction rating exceeds 42? There is evidence.