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TT [ + ) an (nt + x) cos nx dx + [ − - (TT – x) cos nx dx TT -T DO an COSNE n=1 A function f is even if f(-x) = f(x) f

Posted: Thu May 12, 2022 3:28 pm
by answerhappygod
Tt An Nt X Cos Nx Dx Tt X Cos Nx Dx Tt T Do An Cosne N 1 A Function F Is Even If F X F X F 1
Tt An Nt X Cos Nx Dx Tt X Cos Nx Dx Tt T Do An Cosne N 1 A Function F Is Even If F X F X F 1 (19.5 KiB) Viewed 52 times
Hello ,I need solution of this integral by this theorem here, and please integral should be by part.
thank you.
Tt An Nt X Cos Nx Dx Tt X Cos Nx Dx Tt T Do An Cosne N 1 A Function F Is Even If F X F X F 2
Tt An Nt X Cos Nx Dx Tt X Cos Nx Dx Tt T Do An Cosne N 1 A Function F Is Even If F X F X F 2 (106.06 KiB) Viewed 52 times
TT [ + ) an (nt + x) cos nx dx + [ − - (TT – x) cos nx dx TT -T
DO an COSNE n=1 A function f is even if f(-x) = f(x) for all x. If f is even then the Fourier series given by ao f(x) = a + Where 1 f(x) dx -P Sof(x) dx Since f(x) is even 2 P f(x)cosnx dx by = 0.for all n ag 2 z L 562) ao INE an = - [ r(r) Jo • A function f is oddif f(-x) = -f(x) for all x. If f is odd then the Fourier series given by f(x) = bn sinnx x= Σ 00 12=1 Where Qo = 0 an = 0 2 ba f(x) sin ex dx. TE