Answer Happy

4.) "Determine the 95% confidence interval for the proportion of students who regularly eat breakfast in the morning." The class collected sample data and found that 20 out of 25 students regularly eat breakfast in the morning. Describe the error each student made when calculating the confidence interval then give the correct answer: a.) Jackson did the following computation: p==0,8 25 (0.8)(0.2) 25 0.84.08 = (0.72,0.88) 20 error 08 20 pe b.) Emily did the following computation: = 0.8 25 (0.8)(0.2) .08 25 0.8+(0.95).08) = (0.724,0.876) 20 c.) Teresa did the following computation: p=0.8 25 Look up 0.9500 on the normal table: (0.8)(0.2) 25 *2=1.645 0.8.:(1.645).08) → (6684,9316) =.08 d.) Eric did the following computation: 20+1.96 (20)(19) → (12.359,27.641) 25 e.) Correct solution: