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(t+2) y''+3 ty' + 4y = sin t y(3)=2, y'(3)=1
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(t+2) y''+3 ty' + 4y = sin t y(3)=2, y'(3)=1
Posted:
Thu May 12, 2022 10:56 am
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answerhappygod
(t+2) y''+3 ty' + 4y = sin t y(3)=2, y'(3)=1