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Posted: **Thu May 12, 2022 10:23 am**

: 5 5 M 6 M 5 81 2 5 M 2 5 M 2 5 M Skanabisin Menelithic Framing Planning Of 150 M Id Tube 358 Mm 500 Rm Gledex And 320 1 (27.02 KiB) Viewed 41 times

: 5 5 M 6 M 5 81 2 5 M 2 5 M 2 5 M Skanabisin Menelithic Framing Planning Of 150 M Id Tube 358 Mm 500 Rm Gledex And 320 2 (52.4 KiB) Viewed 41 times

: 5 5 M 6 M 5 81 2 5 M 2 5 M 2 5 M Skanabisin Menelithic Framing Planning Of 150 M Id Tube 358 Mm 500 Rm Gledex And 320 3 (41.52 KiB) Viewed 41 times

5.5 m 6 m 5.81 2.5 m 2.5 m 2.5 m Skanabisin menelithic framing planning of 150 m id tube 358 mm * 500 rm gledex and 320 metra lane The Basr bud nede Arza (rash of 15 cileg slet er 75 AP. Feriton bed of 10 w and liner Tom Ford of 21 Pa 31. Calculate the stal factored 100 load in Pa. IN 32. Carcul treballfucured united datud load on girder EF 32, Cautitle ties tair linnale literia muttai பாக்மாப்பா: cindulgida = I'm 34. Cacusie te maimunutmato bending mosent at mdspan starter FS in the factored untom bad Swy 23 kkim 35. Cuculate factoredatear force et face of calumn Ffur gider EFT the factored unikem load iawy - 36. Curcu banding mumul centra mas lal du giner FC 7 led untermodi-sim. INPUT ALL ANSWERS ROUNDED TO THE NEAREST WHOLE NUMBER AN kNm

5.5 m 6 m 5.8 m D A 2.5 m E 2.5 m 1 2.5 m Given above is a monolithic framing plan consisting of 100 mm thick slabs, 250 mm x 500 mm girders and 300 mm square columns The floor load includes floor finish of 1.5 kPa ceiling system of 0.75 kPa p 21 kPa 31. Calculate the total factored floor load in kPa. 32. Calculate the total factored, uniformly distributed load on girder EF. kN/m 33. Calculate the maximum ultimate bending moment at discontinuous end of girder EF. kN/m 34. Calculate the maximum ultimate bending moment at midspan of girder FG in the factored uniform load is wu = 25 kN/m kN.m 35. Calculate the factored shear force at face of column F for girder EF if factored uniform load is wu = 25 kN/m KN 36. Calculate the maximum bending moment continuous left end of girder FG if the factored uniform load is wy = 25 kN/m KN m INPUT ALL ANSWERS ROUNDED TO THE NEAREST WHOLE NUMBER

5.8 m 2.5 m 2.5 m 2.5 m consisting of 100 mm thick slabs, 250 mm x 500 mm girders and 300 mm square columns. The floor load includes floor finish of 1.5 kPa, ceiling system of 0.75 kPa partition load of 10 kPa and floor live load of in kPa y distributed load on girder EF kN/m ding moment at discontinuous end of girder EF. kN/m ding moment at midspan of girder FG in the factored uniform load is wu = 25 kN/m kN.m face of column F for girder EF if the factored uniform load is wu = 25 kN/m KN ment continuous left end of girder FG if the factored uniform load is wy = 25 kN/m KN.m THE NEAREST WHOLE NUMBER