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= 0 < x < 1 The functions u1(x) and u2(x) solve the differential equation u"(x) + g(x)u'(x) + h(x)u(x) = 0, and the func
Posted: Thu May 12, 2022 10:13 am
by answerhappygod
- 0 X 1 The Functions U1 X And U2 X Solve The Differential Equation U X G X U X H X U X 0 And The Func 1 (98.36 KiB) Viewed 22 times
= 0 < x < 1 The functions u1(x) and u2(x) solve the differential equation u"(x) + g(x)u'(x) + h(x)u(x) = 0, and the function w(x) solves the differential equation u'(x) + g(x)u'(x) +h(x)u(x) = f(x), Furthermore, we have the data in the table below. = 0<x< 1 w'(x) 0 -0.1 : х u(x) ui'(x) u2(x) uz'(x) w(x) 0 1 0 0 1 0 0.1 1.1 0.1 0.1 1.1 -0.1 : : : : : 1 2 1 2 2 -1 Write the solution to the boundary value problem u"(x) + g(x)u'(x) +h(x)u(x) = f(x), 0 < x < 1 u(0) = -2, u(1) = 2 in terms of u1(x), u2(x) and w(x). -2 = =