3) Use the definition of Laplace Transform to evaluate £ {f(t)}, where (1,2) (3,2) 2 1 1 2 3 4 5
Posted: Thu May 12, 2022 10:04 am
I know it's f(t) = {(2t, 0<t<1), (2,
1<t<3), (-t+5, 3<t<5)} the integral for 2,
1<t<3 is [(4e^-2s * Sinh(s))/s] and I don't understand
why.
3) Use the definition of Laplace Transform to evaluate £ {f(t)}, where (1,2) (3,2) 2 1 1 2 3 4 5
1<t<3), (-t+5, 3<t<5)} the integral for 2,
1<t<3 is [(4e^-2s * Sinh(s))/s] and I don't understand
why.
3) Use the definition of Laplace Transform to evaluate £ {f(t)}, where (1,2) (3,2) 2 1 1 2 3 4 5