Answer Happy

2 51 Let A = and b = Show that the equation Ax=b does not have a solution for some choices of b, and describe the set of all b for which Ax=b does have a solution. -8 -4 b2 How can it be shown that the equation Ax=b does not have a solution for some choices of b? O A. Find a vector x for which Ax=b is the identity vector. OB. Find a vector b for which the solution to Ax=b is the identity vector. O C. Row reduce the matrix A to demonstrate that A does not have a pivot position in every row. OD. Row reduce the augmented matrix [ A b ] to demonstrate that [ A b ] has a pivot position in every row. O E. Row reduce the matrix A to demonstrate that A has a pivot position in every row. Describe the set of all b for which Ax=b does have a solution. The set of all b for which Ax=b does have a solution is the set of solutions to the equation 0 = 6 + b2. (Type an integer or a decimal.)