д?и дги дги + + дх2 = 0 ду? дz2 (0 < x <1, 0< у < 1, 0 < x < 1) и(0, y, z) = 0, u(1,y,z) = 0, u(x, 0,z) = 0, (x, 1,z) =
Posted: Thu May 12, 2022 7:48 am
д?и дги дги + + дх2 = 0 ду? дz2 (0 < x <1, 0< у < 1, 0 < x < 1) и(0, y, z) = 0, u(1,y,z) = 0, u(x, 0,z) = 0, (x, 1,z) = 0, = = и(x, y, 0) = 0, u(x, y, 1) = sin(пх) sin(2пу) =