11 g (t) - = sin (bt) + cos (6) ] f(t) = cos (bt) - sin (bt) 37 h(t)= 2 sin (4+) - cos (46) 4] f(t)= 3 sin (36) - cos. (
Posted: Wed May 11, 2022 9:41 pm
Answer Them all
answer 1 till 4
Answer 1 to 3
11 g (t) - = sin (bt) + cos (6) ] f(t) = cos (bt) - sin (bt) 37 h(t)= 2 sin (4+) - cos (46) 4] f(t)= 3 sin (36) - cos. (Lt) t sin (46
j g/H) = sin (b) + ces (6) lt) + 2 f(t)= cos (bt) - sin (6t) 37 h(t)= a sin (4+)- cos (46) 2 )
answer 1 till 4
Answer 1 to 3
11 g (t) - = sin (bt) + cos (6) ] f(t) = cos (bt) - sin (bt) 37 h(t)= 2 sin (4+) - cos (46) 4] f(t)= 3 sin (36) - cos. (Lt) t sin (46
j g/H) = sin (b) + ces (6) lt) + 2 f(t)= cos (bt) - sin (6t) 37 h(t)= a sin (4+)- cos (46) 2 )