Find the Fourier series for the function, f(t) = {-1 for – 1
Posted: Wed May 11, 2022 8:54 pm
Find the Fourier series for the function, f(t) = {-1 for – 1<t<- 1/2; 0 for – 1/2<t< 1/2; 1 for 1/2<t< T} f(t) = (2/TT)(sint + sin2t + (1/3)sin3t +...) f(t) = (2/TT)(sint - sin2t+ (1/3)sin3t +...) f(t) = (1/TT)(sint - (1/2)sin2t + (1/3)sin3t +...) Of(t) = (1/1)(1 + sint - sin2t +(1/3)sin3t +...)
Posted: Wed May 11, 2022 8:54 pm
Find the Fourier series for the function, f(t) = {-1 for – 1<t<- 1/2; 0 for – 1/2<t< 1/2; 1 for 1/2<t< T} f(t) = (2/TT)(sint + sin2t + (1/3)sin3t +...) f(t) = (2/TT)(sint - sin2t+ (1/3)sin3t +...) f(t) = (1/TT)(sint - (1/2)sin2t + (1/3)sin3t +...) Of(t) = (1/1)(1 + sint - sin2t +(1/3)sin3t +...)